I'm getting ready to close off the leading edge of my 2+2 wing and I installed a light weight conduit to later pull wire through for the nav and landing lights. I tried to figure out the wire size using AC43-13B but didn't make much sense out of it, sorry to say. The nav lights will be L E D so they will be very low current draw; about 1 watt each. Each wing will have one L E D landing light drawing 8.8 watts. I sure could use some help either figuring out how to use the chart in AC43-13 or an idea as to what size wire to use for the application. Each wing conduit will need to run the power wire for the nav light and a power wire for the landing light. I will need to run a ground wire also (wood wing); should I run a separate one to each light or one in each wing and branch off to each light? Thanks in advance; I'm out of my element as I start to think ahead to electrical.
Thanks,
Marty57
Hi Marty
Use the chart from the AC 43-13. But first calculate your current draw for each light.
Watts = volts X amps, so if we juggle the formula we can get amps by using watts/volts = amps [1/12=.08]. Looking at the chart (for continuous current flow) lets use the diagonal line for 1 amp and estimate 25 feet of wire. Use the 1 amp line as its the smallest amount of current shown on the chart and use the 25 foot length as a good estimate and it falls on a horizontal line. Now trace the 1 amp line down and trace the 25 foot line from left to right, until they intersect. In this case they intersect between the columns for 24 gauge and for 22 gauge, so round up to the 22 gauge. NEVER round down as this will result in a to small wire for the current flow.
Now to calculate the breaker size, add the total current flow for each of the three nav lights, 3 X .08 = .24 amps. Since the breaker is intended to protect the wire and not the components, we are safe in using a 1 amp breaker on the nav light system. Remember that we used 1 amp in our wire calculations. If any one wire shorts out, the breaker will open at 1 amp and the wire is large enough to handle that 1 amp and not be damaged.
Do the same for the landing lights. Watts/volts = amps [8.8/12 = .73]. Round this up to 1 amp for each light and double that as you have one light on each wing. Find the 2 amp diagonal line on the chart and trace it down until it intersects with the 25 foot horizontal line. In this case it falls right on the 20 gauge column. If we install a two amp breaker, we will have enough power to operate the landing lights and have protection for each individual wire. I know that some of you are saying 'surge current' and 'derating factor' right now. Experience has shown me that LEDs have a very even current flow and not much of a surge current on start up, so these are safe calculations.
Just some tips from my experience:
Use single conductor, shielded wire, so you can run power on the center conductor and use the outer shield for your ground path. I do this on wings with a metal spar, too. Helps me avoid ground problems from paint and powder coating. Also is the best way to wire lights in rudders. It gives you a continuous ground path independent of the rudder hinges. No more blinking lights during taxi!
Avoid using wire smaller than 22 gauge for airframe systems. They require smaller than standard terminals and lack the mechanical strength to withstand vibration and abuse. These smaller terminals are expensive and require special tooling. Anyone telling you to do things like double the conductor to get it to crimp into standard size terminals is not your friend. Just remember me telling you that it's not good shop practice, it's unprofessional, and they're a hack.
You didn't do yourself many favors with the corrugated conduit. It's difficult to route wires through. I've never been a fan of using a conduit unless it has a special use to protect the wire from mechanical damage. Light wires are enclosed after installation, so I don't see the need. Since the wing is still fairly open, why not route the wires now?
If you do much electrical work, study up on the charts in the AC 43-13. One is for continuous current flow and one is for intermittent flow. The continuous flow chart is the most useful. Start with the voltage of your circuit and you can calculate wire size, wire length, current capacity for a specific size of wire, and correct breaker size.
Let me know if I can help you out.
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